\(2Fe+3Cl_2\rightarrow2FeCl_3\)
\(2Al+3Cl_2\rightarrow2AlCl_3\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(Al\left(OH\right)_3+NaOH\rightarrow NaAlO_2+2H_2O\)
\(n_{Fe\left(OH\right)3}=\frac{2,14}{107}=0,02\left(mol\right)\)
\(\Rightarrow n_{Fe}=0,02\left(mol\right)\)
\(m_{Fe}=0,02.56=1,12\left(g\right)\)
\(m_{Al}=1,39-1,12=0,27\left(g\right)\)
\(n_{Al}=\frac{2,7}{27}=0,1\left(mol\right)\)
\(\Rightarrow n_{Cl2}=0,02.1,5+0,01.1,5=0,045\left(mol\right)\)
\(\Rightarrow V_{Cl2}=0,45.22,4=10,08\left(l\right)\)
\(m=m_{AlCl3}+m_{FeCl3}=4,585\left(g\right)\)