Bài 1 tìm các giới hạn sau :
a, lim 2x²-3x-2/x-2
(limx->2)
b, lim x³-3x²+5x-3/x²-1
(limx->1)
c, limx²+2x/x²+4x+4
(limx->2)
d, limx³-x²-x+1/x²-3x+2
(lim x->1)
e, limx³-5x²+3x+9/x4-8x²-9
(lim x->1)
f, lim x4-1/x³-2x²+3
(limx->-1)
g, limx²+2x-3/2x²-x-1
(limx->1)
h,lim x³-3x+2/4-x²
(lim x->-2)
i, lim4x6-5x5+1/x²-1
(lim x->1)
k, lim x mũ m -1/ x mũ n -1
(lim x->1)m, n thuộc N
tìm các giới hạn sau:
a; \(\lim\limits_{x\rightarrow1}\frac{2x^4-5x^3+3x^2+1}{3x^4-8x^3+6x^2-1}\)
b; \(\lim\limits_{x\rightarrow1}\frac{x^3-3x^2+2}{x^4-4x+3}\)
c; \(\lim\limits_{x\rightarrow1}\frac{x^3-2x-1}{x^5-2x-1}\)
d; \(\lim\limits_{x\rightarrow-1}\frac{\left(x+2\right)^2-1}{x^2-1}\)
Câu 1:
a, limx→-∞ \(\dfrac{x+\sqrt{x^2+2}}{\sqrt{8x^2+5x+2}}\)
b, limx→-∞ \(\dfrac{\sqrt{x^2+2x}+3x}{\sqrt{4x^2+1}-x+2}\)
c, limx→-∞ \(\dfrac{x+\sqrt{x^2+x}}{3x-\sqrt{x^2+1}}\)
d, limx→-∞ \(\dfrac{\sqrt{x^2+x+2}+3x}{\sqrt{4x^2+1}-x+1}\)
\(\lim\limits_{x\rightarrow0}\dfrac{\left(1+3x\right)^3-\left(1-4x\right)^4}{x}\)
\(\lim\limits_{x\rightarrow2}\dfrac{2x^2-5x+2}{x^3-3x-2}\)
\(\lim\limits_{x\rightarrow1}\dfrac{x^4-3x+2}{x^3+2x-3}\)
tìm các giới hạn sau:
a, \(\lim\limits_{x\rightarrow1}\frac{x^4-1}{x^3-2x^2+1}\) ( câu a,b chỉ cần thay số vào thôi đúng k ạ nếu là thay số thì k cần trình bày nữa đâu )
b, \(\lim\limits_{x\rightarrow-1}\frac{x^5+1}{x^3+1}\)
c, \(\lim\limits_{x\rightarrow3}\frac{x^3-5x^2+3x+9}{x^4-8x^2-9}\)
d, \(\lim\limits_{x\rightarrow1}\frac{x-5x^5+4x^6}{\left(1-x\right)^2}\)
e, \(\lim\limits_{x\rightarrow1}\frac{x^m-1}{x^n-1}\)
f, \(\lim\limits_{x\rightarrow-2}\frac{x^4-16}{x^3+2x^2}\)
Bài 1
a. \(\lim\limits_{x\rightarrow-\infty}\frac{\sqrt{4x^2}+1}{3x-1}\)
b. \(\lim\limits_{x\rightarrow+\infty}\frac{\sqrt{9x^2+x+1}-\sqrt{4x^2+2x+1}}{x+1}\)
c. \(\lim\limits_{x\rightarrow+\infty}\frac{\sqrt{x+2x+3}+4x+1}{\sqrt{4x^2+1}+2-x}\)
d. \(\lim\limits_{x\rightarrow+\infty}\frac{3x-2\sqrt{x}+\sqrt{x^4-5x}}{2x^2+4x-5}\)
Bài 2
a. \(\lim\limits_{x\rightarrow-\infty}\frac{2x+1}{x-1}\)
b. \(\lim\limits_{x\rightarrow-\infty}\frac{2x^3+3}{x^3-2x^2+1}\)
c. \(\lim\limits_{x\rightarrow+\infty}\frac{\left(3x^2+1\right)\left(5x+3\right)}{\left(2x^3-1\right)\left(x+4\right)}\)
a. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{1+2x}-1}{2x}\) f. \(\lim\limits_{x\rightarrow1}\frac{\sqrt{2x+7-3}}{2-\sqrt{x+3}}\)
b. \(\lim\limits_{x\rightarrow0}\frac{4x}{\sqrt{9+x}-3}\) g. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{x^2+1}-1}{\sqrt{x^2+16}-4}\)
c. \(\lim\limits_{x\rightarrow2}\frac{\sqrt{x+7}-3}{x-2}\) h. \(\lim\limits_{x\rightarrow4}\frac{\sqrt{x+5}-\sqrt{2x+1}}{x-4}\)
d. \(\lim\limits_{x\rightarrow1}\frac{3x-2\sqrt{4x^2-x-2}}{x^2-3x+2}\) k. \(\lim\limits_{x\rightarrow0}\frac{\sqrt{x+1}+\sqrt{x+4}-3}{x}\)
e. \(\lim\limits_{x\rightarrow1}\frac{\sqrt{2x+7}+x-4}{x^3-4x^2+3}\)
Tính các giới hạn sau:
Câu 1:
a, limx→\(\pm\)∞ \(\dfrac{\left(2x-3\right)^2\left(4x+7\right)^3}{\left(3x-4\right)^2\left(5x^2-1\right)}\)
b, limx→\(\pm\)∞ \(\dfrac{\sqrt[3]{x^3+2x^2+x}}{2x-2}\)
c, limx→\(\pm\)∞ \(\dfrac{\sqrt[3]{\left(x^3+2x^2\right)^2}+x^3\sqrt{x^3+2x^2}+x^2}{3x^2-2x}\)
d, limx→+∞ \(\dfrac{\left(2-3x\right)^3\left(x+1\right)^2}{1-4x^5}\)
e, limx→+∞ \(\dfrac{\left(2x-3\right)^{20}\left(3x+2\right)^{20}}{\left(2x+1\right)^{50}}\)
g, limx→+∞ \(\dfrac{\left(2x-3\right)^3\left(4x^5+7\right)^9}{11x^{47}-8}\)
Biết lim x -> +∞ f(x) = M ;lim x -> +∞ g(x) = 0 Chọn khẳng định đúng? A. Lim x -> +∞ f(x)/g(x)= +∞ B. Lim x -> +∞ = f(x)/g(x)= -∞ C. Lim x -> +∞ f(x)/g(x)=0 D. Limx -> +∞ [g(x).f(x)]=0
Câu 1:
a, limx→+∞ (\(\sqrt{x+1}-\sqrt{x}\))
b, limx→+∞ (\(\sqrt{x+\sqrt{x}}-\sqrt{x}\))
c, limx→-∞ (\(\sqrt{3x^2+x+1}+x\sqrt{3}\))
d, limx→+∞ (\(\sqrt{x^2+2x+4}-\sqrt{x^2-2x+4}\))