Question

Ai giúp em với

Answer 1

a: Ta có: \(P=\dfrac{x^2+x-2}{x^2-3x}\cdot\left(\dfrac{\left(x+2\right)^2-x^2}{4x^2-4}-\dfrac{3}{x^2-x}\right)\)

\(=\dfrac{\left(x+2\right)\left(x-1\right)}{x\left(x-3\right)}\cdot\left(\dfrac{1}{x-1}-\dfrac{3}{x\left(x-1\right)}\right)\)

\(=\dfrac{\left(x+2\right)\left(x-1\right)}{x\left(x-3\right)}\cdot\dfrac{x-3}{x\left(x-1\right)}\)

\(=\dfrac{x+2}{x^2}\)