Question

a²+4ab+b²/a²-4b²=a+2b/a-2b

Answer 1

\(\dfrac{a^2+4ab+4b^2}{a^2-4b^2}=\dfrac{\left(a+2b\right)^2}{\left(a-2b\right)\left(a+2b\right)}=\dfrac{a+2b}{a-2b}\)