a) Ta có: \(4.NTK_{Mg}=3.NTK_X\)
`=>` \(NTK_X=\dfrac{24.4}{3}=32\left(đvC\right)\)
`=> X: S`
b) Ta có: \(\left\{{}\begin{matrix}NTK_{Fe}=56\left(đvC\right)\\NTK_S=32\left(đvC\right)\\NTK_{Si}=28\left(đvC\right)\end{matrix}\right.\)
`=>` \(Fe>S>Si\)
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