1) Cho \(\dfrac{x}{3}=\dfrac{y}{2}\) và x.\(y^2\)=324. Tìm x,y
2) Tìm các số tự nhiên x,y bik \(2^{x+1}.3^y=4^x.3^x\)
3) CMR nếu có tỉ lệ thức \(\dfrac{a}{b}=\dfrac{c}{d}\) thì ta có \(\left(\dfrac{a-b}{c-d}\right)^4=\dfrac{a^4+b^4}{c^4+d^4}\)
4) Tính: B=\(\dfrac{27^{15}.5^3.8^4}{25^2.81^{11}.2^{11}}\)
1) \(\dfrac{x}{3}=\dfrac{y}{4}=t\Leftrightarrow\left\{{}\begin{matrix}x=3t\\y=4t\end{matrix}\right.\)
ta có \(x.y^2=324\Leftrightarrow3t.\left(4t\right)^2=324\)
\(\Leftrightarrow t^3=\dfrac{27}{4}\)
\(\Leftrightarrow t=\dfrac{3}{\sqrt[3]{4}}\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=3.\dfrac{3}{\sqrt[3]{4}}=\dfrac{9}{\sqrt[3]{4}}\\y=4.\dfrac{3}{\sqrt[3]{4}}=\dfrac{12}{\sqrt[3]{4}}\end{matrix}\right.\)
2) \(2^{x+1}.3^y=2^{2x}.3^x\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+1=2x\\x=y\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)
3) \(\dfrac{a}{b}=\dfrac{c}{d}\)
áp dụng dãy tỉ số = nhau ta có
\(\dfrac{a}{b}=\dfrac{c}{d}=\dfrac{a-c}{b-d}\)
\(\Leftrightarrow\dfrac{a^4}{b^4}=\dfrac{c^4}{d^4}=\left(\dfrac{a-c}{b-d}\right)^4\left(1\right)\)
mà \(\dfrac{a^4}{b^4}=\dfrac{c^4}{d^4}=\dfrac{a^4+c^4}{b^4+c^4}\left(2\right)\)
từ (1)(2) suy ra đpcm
4) \(B=\dfrac{27^{15}.5^3.8^4}{25^2.81^{11}.2^{11}}=\dfrac{\left(3^3\right)^{15}.5^3.\left(2^3\right)^4}{\left(5^2\right)^2.\left(3^4\right)^{11}.2^{11}}=\dfrac{3^{45}.5^3.2^{12}}{5^4.3^{44}.2^{11}}=\dfrac{3.2}{5}=\dfrac{6}{5}\)