Question

Answer 1

\(\left\{{}\begin{matrix}2x-3y=5\\4x+7y=8\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}4x-6y=10\\4x+7y=8\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}-13y=2\\2x-3y=5\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y=-\dfrac{2}{13}\\2x=3y+5=3\cdot\dfrac{-2}{13}+5=-\dfrac{6}{13}+5=\dfrac{65-6}{13}=\dfrac{59}{13}\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=\dfrac{59}{26}\\y=-\dfrac{2}{13}\end{matrix}\right.\)