Question

Answer 1

a) \(\left\{{}\begin{matrix}2A+3G=2356\\A-G=148\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}A=T=560\left(nu\right)\\G=X=412\left(nu\right)\end{matrix}\right.\)

b) Tổng số nu : N = 2A + 2G = 1944 (nu)

Chiều dài

L = 3,4N/2 = 3204,3A^o

c) Số aa trong chuỗi polipeptit:

1944/6 - 1 = 323 (aa)

Answer 2

Thi hả bn

Answer 3

Theo bài ta có : \(\left\{{}\begin{matrix}2A+3G=2356\\A-G=148\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}A=T=560\left(nu\right)\\G=X=412\left(nu\right)\end{matrix}\right.\)

\(\Rightarrow L=\dfrac{3,4.N}{2}=\dfrac{3,4.\left(2A+2G\right)}{2}=\dfrac{16524}{5}\left(\overset{o}{A}\right)\)

- Số \(aa\) là : \(\dfrac{2A+2G}{6}-1=\dfrac{994}{3}\left(aa\right)\)

- Đề có sai không vậy ?