Question

Answer 1

\(PTK_{hc}=74\left(\text{đ}.v.C\right)\\ \Leftrightarrow NTK_{Ca}+17x=74\\ \Leftrightarrow40+17x=74\\ \Leftrightarrow x=2\\ \Rightarrow CTHH:Ca\left(OH\right)_2\)

Answer 2

PTK của hợp chất`=74(đvC)`

`Ca+16x+1x=74`

`40+17x=74`

`x=2`

=>CT đúng:`Ca(OH)_2`