\(\Leftrightarrow3x^3-3x^3-2x^2+2x+2x-2-1⋮x-1\)
\(\Leftrightarrow x-1\in\left\{1;-1\right\}\)
hay \(x\in\left\{2;0\right\}\)
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⇔3x3−3x3−2x2+2x+2x−2−1⋮x−1⇔3x3−3x3−2x2+2x+2x−2−1⋮x−1
⇔x−1∈{1;−1}⇔x−1∈{1;−1}
hay x∈{2;0}
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