Câu 19:
\(\overrightarrow{BD}=\dfrac{1}{3}\left(\overrightarrow{BA}+\overrightarrow{AC}\right)=\dfrac{-1}{3}\overrightarrow{AB}+\dfrac{1}{3}\overrightarrow{AC}\)
\(\overrightarrow{AD}=\overrightarrow{AB}+\overrightarrow{BD}=\dfrac{2}{3}\overrightarrow{AB}+\dfrac{1}{3}\overrightarrow{AC}\)
Chọn A