Question

Answer 1

\(f\left(x\right)=ax^5+b^3+2014x+1\)

⇒\(f\left(-x\right)=a\left(-x\right)^5+b\left(-x\right)^3+2014\left(-x\right)+1\)

= \(-ax^5-bx^3-2014x+1\)

⇒ \(f\left(x\right)+f\left(-x\right)=2\)

⇒\(f\left(2015\right)+f\left(-2015\right)=2\)

Mà \(f\left(2015\right)=2\Rightarrow f\left(-2015\right)=0\)

Answer 2

\(f\left(x\right)=ax^5+bx^3+cx-5\\ \Leftrightarrow f\left(-3\right)=-243a-27b-3c-5=208\\ \Leftrightarrow-243a-27b-3c=213\\ \Leftrightarrow243a+27b+3c=-213\\ \Leftrightarrow f\left(3\right)=243a+27b+3c-5=-213-5=-218\)

Tick nha