ĐK : x khác +- 3
pt <=> \(\dfrac{\left(x+2\right)\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-\dfrac{x+3}{\left(x-3\right)\left(x+3\right)}=\dfrac{x^2}{\left(x-3\right)\left(x+3\right)}\)
=> x2 - 2x - 9 = x2
<=> -2x = 9 <=> x = -9/2 (tm)
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