Tìm x)

x(1-2x) +(x-2).(2x-3) = 0

x(2x -4) -2x (x+3) =0

(2x+3)²+(x-3).(2x+3) =0

10y² -2xy +25 +x² +30y

(2x-1)² +(2x+1)² -2(2x-2)(2x+1) +x = 12

TÌm x:

( x + 2)⁴ + (x -4) ⁴ = 162

x² - 5x - 21 = 0

x² - (x+1)² = 0

(x - 1).(x+2) - x-2= 0

x² - 4x +3 = 0

3x ( x-4) +12x - 48 = 0

(2x-1).(5-3x) = (x+2).(5-3x)

Phân tích đa thức thành nhân tử:

y³ - 25y - 4xy² + 4x²y

(2x - y +4)² - 2(y-4) .( 2x - y + 4) + (y-4)

Tìm x

a) 3x-6 = (x-1).(x-2)

b) (x-2).(x+2) + (2x+1)²- 5x(x-3)=5

Tìm x biết:

4x² - 6x = 0

b) 4x² + 4x = -1

c) 5x² + x = 0

d) x³ - 5x = 4x²

3x(x-2) = x-2

x³ - 16x = 0