Giải Phương Trình

\(\sqrt{x-2}+4\sqrt{3x+7}=x^2-4x+20\)

Cho x=\(\frac{\sqrt{3+\sqrt{2}}}{\sqrt{3+\sqrt{2}}}\)và y=\(\frac{\sqrt{3-\sqrt{2}}}{\sqrt{3+\sqrt{2}}}\)

Tính A=5x²+6xy+5y²

\(\left(\frac{b}{b+8}-\frac{4b}{\left(\sqrt[3]{b}+2\right)^3}\right).\left(\frac{1+2\sqrt[3]{\frac{1}{b}}}{1-2\sqrt[3]{\frac{1}{b}}}\right)-\frac{24}{b+8}\)

A=\(\frac{\sqrt[3]{a^4}+\sqrt[3]{a^2b^2}+\sqrt[3]{b^4}}{\sqrt[3]{a^2}+\sqrt[3]{a^{ }b^{ }}+\sqrt[3]{b^2}}\)

B=\(\frac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4-2}}{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4+2}}\)

B=\(\frac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4}-2}{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4}+2}\)

Rút gọn

Help meeee

Please!!!!

B=\(\frac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4-2}}{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4+2}}\)

Rút gọn

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