oke các trưởng bối

\(d,=\left(\dfrac{6}{25}+\dfrac{9}{25}\right)+\left(\dfrac{7}{48}+\dfrac{17}{48}\right)\\ =\dfrac{15}{25}+\dfrac{24}{48}\\ =\dfrac{1}{5}+\dfrac{1}{2}\\ =\dfrac{2.1+5.1}{10}\\ =\dfrac{2+5}{10}=\dfrac{7}{10}\\ @Dosea\)

That house is too expensive , so  he isn't buying it

\(A=\left(\dfrac{4}{7}+\dfrac{10}{7}\right)+\left(\dfrac{11}{9}+\dfrac{7}{9}\right)\\ =\dfrac{14}{7}+\dfrac{18}{9}\\ =2+2=4\\ B=\left(\dfrac{1}{6}+\dfrac{5}{6}\right)+\left(\dfrac{7}{12}+\dfrac{5}{12}\right)\\ =\dfrac{6}{6}+\dfrac{12}{12}\\ =1+1=2\)

\(C=\left(\dfrac{1}{26}+\dfrac{12}{26}\right)+\left(\dfrac{7}{30}+\dfrac{8}{30}\right)\\ =\dfrac{13}{26}+\dfrac{15}{30}\\ =\dfrac{1}{2}+\dfrac{1}{2}\\ =\dfrac{2}{2}=1\\ D=\left(\dfrac{6}{25}+\dfrac{9}{25}\right)+\dfrac{7}{48}+\dfrac{17}{47}\\ =\dfrac{15}{25}+\dfrac{7}{48}+\dfrac{17}{47}\\ =\dfrac{3}{5}+\dfrac{7}{48}+\dfrac{17}{47}??\)

hình như sai đề câu d

\(@Dosea\)

Before he came here , he had finished his work

\(\dfrac{5}{9};\dfrac{11}{18};\dfrac{11}{15};\dfrac{14}{15}\\ \\ \dfrac{9}{30};\dfrac{7}{15};\dfrac{5}{6};\dfrac{8}{3}\\ @Dosea\)

\(4,\\ 2^3< 2^x\le2^6\\ 3< x\le6\\ =>x=\left\{4;5;6\right\}\\ =>B\\ @Dosea\)

\(c,\left(x-2\right)^2-\left(x-2\right)^3=0\\ \left(x-2\right)^2\left(x-2-1\right)=0\\ \left(x-2\right)^2\left(x-3\right)=0\\ =>x=2;x=3\\ d,\left(3x-2\right)=7\\ 3x-2=7\\ 3x=7+2\\ 3x=9\\ x=9:3\\ x=3\\ @Dosea\)