Question

(-x^2*y)^3*1/2*x^2*y^3*(-2*x*y^2*z)^2

giup vs a

Answer 1

\(\left(-x^2y\right)^3\cdot\dfrac{1}{2}\cdot x^2y^3\cdot\left(-2xy^2z\right)^2\\ =-x^6y^3\cdot\dfrac{1}{2}x^2y^3\cdot4x^2y^4z^2\\ =\left(-1\cdot\dfrac{1}{2}\cdot4\right)\cdot\left(x^6\cdot x^2\cdot x^2\right)\cdot\left(y^3\cdot y^3\cdot y^4\right)\cdot z^2\\ =-2x^{10}y^{10}z^2\)

Answer 2

bạn chụp ảnh sẽ dễ nhìn hơn :D

Answer 3

`(-x^2y)^3. 1/2x^2y^3(-2xy^2z)^2`

`=(-1/2).x^6y^3.x^2y^3.4x^2y^4z^2`

`=(-1/2).4.x^{6+2+2}.y^{3+3+4}.z^2`

`=-2x^10y^10z^2`

Answer 4

Ta có: \(\left(-x^2y\right)^3\cdot\left(\dfrac{1}{2}x^2y^3\right)\cdot\left(-2xy^2z\right)^2\)

\(=x^6y^3\cdot\dfrac{1}{2}x^2y^3\cdot4x^2y^4z^2\)

\(=2x^{10}y^{10}z^2\)