Tìm nghiệm của pt
x^2+5y^2-4xy+6x-13y+9=0
Rút gọn A=3x-2y+{3x-2x-[y+2x-(5x+y)] -4(2x-5y)}
Biết x=a2-2ab+b2 va y=a2+2ab+b2
Bài 1 ) Tìm x
a) x-1 và 8-x có BC(10)
b)3x-2 và 11-2x có một BC(35
Bài 2) tìm x
a)2+4+6+8+......+2x
b)tìm x và y '
(8-2x)(11-5y)=6
B1 GPT
a,\(\left\{{}\begin{matrix}x^3=5x+y\\y^3=5y+x\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}x^2+y^4=20\\x^4+y^2=20\end{matrix}\right.\)
c,\(\sqrt{x+1}=x^2+4x+5\)
\(\frac{1}{2\left(x-1\right)}+\frac{3}{x^2-1}=\frac{1}{4}\)
\(\frac{x-1}{x}-\frac{3x}{2x-2}=-\frac{5}{2}\)
\(\frac{x+2}{2x-3}-\frac{1}{2x+3}=1-\frac{2x^2-x-4}{4x^2-9}\)
B1: GPT
a,\(\left\{{}\begin{matrix}x^2+y^2-x+y=2\\xy+x-y=-1\end{matrix}\right.\) c,\(\left\{{}\begin{matrix}x^3=5x+y\\y^3=5y+x\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}xy-x+y=-3\\x^2+y^2-x+y+xy=6\end{matrix}\right.\) d,\(\left\{{}\begin{matrix}x^2+y^4=20\\x^4+y^2=20\end{matrix}\right.\)
x3-6x+9x-2=0
-x4+2x3+4x2-7x+2=0
(x-2)(x2+3x+1)=x2-4
(x2+5x)2-2(x2+5x)-24=0
(4+x)2-(x-1)3=(1-x)(x2-2x+17)
(4x+3)2(x+1)(2x+1)=810
\(\frac{x^3+2x-8}{x^2-2x+3}=\left(x+1\right)\left(\sqrt{x+2}-2\right)\)
\(\sqrt{2x-3}=x-3\)
\(\sqrt{x^2+x-12}=8-x\)
\(\sqrt{x^2+2x+4}=\sqrt{2-x}\)
\(\sqrt{x^2-3x}=\sqrt{2x-1}\)
