Question

(x+1)*(x-1)*(x+2)*(x-2)

Answer 1

(x+1)(x-1)(x+2)(x-2)

= (x² - 1)(x² -4)

= x⁴ - 4x² - x² + 4

= x⁴ - 5x² + 4

Answer 2

Ta có: \(\left(x+1\right)\left(x-1\right)\left(x+2\right)\left(x-2\right)\)

= \(\left(x^2-1\right)\left(x^2-4\right)\)

= \(x^4-4x^2-x^2+4\)

= \(x^4-5x^2+4\)

Vậy \(\left(x+1\right)\left(x-1\right)\left(x+2\right)\left(x-2\right)=x^4-5x^2+4\)

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Answer 3

\(\left(x+1\right)\left(x-1\right)\left(x+2\right)\left(x-2\right)\\ =\left(x^2-1\right)\left(x^2-4\right)\\ =x^4-5x^2+4\)

Answer 4

\(\left(x+1\right)\left(x-1\right)\left(x+2\right)\left(x-2\right)\)

\(=\left(x^2-1\right)\left(x^2-4\right)\)

\(=x^4-4x^2-x^2+4=x^4-5x^2+4\)