\(x+\dfrac{3}{13}=\dfrac{10}{13}\)
\(\Leftrightarrow\)\(x=\dfrac{10}{13}-\dfrac{3}{13}\)
\(\Leftrightarrow\)\(x=\dfrac{7}{13}\)
\(x+\dfrac{3}{13}=\dfrac{10}{13}\Rightarrow x=\dfrac{10}{13}-\dfrac{3}{13}\Rightarrow x=\dfrac{7}{13}\)
Ta có: \(x+\dfrac{3}{13}=\dfrac{10}{13}\)
nên \(x=\dfrac{10}{13}-\dfrac{3}{13}\)
hay \(x=\dfrac{7}{13}\)