(x -2) .(2y +3)= 26
=>x -2 ;2y +3\(\in\)U(26)
U(26)={\(\pm1;\pm2;\pm13;\pm26\)}
=>x - 2 ;2y +3\(\in\){\(\pm1;\pm2;\pm13;\pm26\)}
ta có bảng sau:
| x-2 | -1 | -26 | 1 | 26 | 2 | 13 | -13 | -2 |
| 2y+3 | -26 | -1 | 26 | 1 | 13 | 2 | -2 |
-13 |
| x | 1 | -24 | 3 | 28 | 4 | 15 | -11 | 0 |
| y | \(\varnothing\) | -2 | \(\varnothing\) | -1 | 5 | \(\varnothing\) | \(\varnothing\) | -8 |
=>x=-24 thì y=-2
x=28 thì y=-1
x=4 thì y=5
x=0 thì y=-8
Đúng 0
Bình luận (0)
