\(\left(a-1\right)^3-\left(a+1\right)^3=a^3-3a^2+3a-1-a^3-3a^2-3a-1=-6a^2-2=-2\left(3a^2+1\right)\)
Đúng 0
Bình luận (0)
Violympic toán 8
Các câu hỏi tương tự
viet cac bieu thuc sau duoi dang tich:
b,(a-1)\(^3\)-(a+1)\(^3\)
viet cac bieu thuc sau duoi dang tich:
a, -64+(x-3)\(^3\)
viet cac bieu thuc sau duoi dang tich:
a, -64+(x-3)\(^3\)
viet cac bieu thuc sau duoi dang tich: x^3 y^3+225
viet cac bieu thuc sau duoi dang tich;
a,x\(^3\)y\(^3\)+225
viet cac bieu thuc sau duoi dang tich:
a, a\(^6\)-b\(^6\)
viet cac bieu thuc sau duoi dang tong:
a,(4-xy)^3
b,(0,1+xy)^3
viet cac bieu thuc sau duoi dang tich:
a,1,24\(^3\)-0,24\(^3\)
b,(a-1)\(^3\)+(a+1)\(^3\)
c, a\(^6\)-b\(^6\)
viet cac bieu thuc sau duoi dang tong:
a,(-3x+2)\(^3\)