\(\sqrt{3+\sqrt{5}}-\sqrt{3-\sqrt{5}}-\sqrt{2}=\dfrac{\sqrt{6+2\sqrt{5}}-\sqrt{6-2\sqrt{5}}-2}{2}=\dfrac{\sqrt{\left(\sqrt{5}+1\right)^2}-\sqrt{\left(\sqrt{5}-1\right)^2}-2}{2}=\dfrac{\left|\sqrt{5}+1\right|-\left|\sqrt{5-1}\right|-2}{2}=\dfrac{\sqrt{5}+1-\sqrt{5}+1-2}{2}=\dfrac{0}{2}=0\)