Question

tính số mol NO2 trong 13,44 lít khí NO2 ở đktn

Answer 1

\(n_{NO2}=\dfrac{13,44}{22,4}\approx0,6\left(mol\right)\)

Answer 2

\(n_{NO2}=\dfrac{V}{22,4}=\dfrac{13,44}{22,4}=0,6\left(mol\right)\)

Answer 3

\(^{ }\)\(^n\)NO\(_2\)= \(\dfrac{V_{NO_2}}{22,4}\)= \(\dfrac{13,44}{22,4}\)= 0,6 (mol)