\(m_{NaCL}=0,1.58,5=5,85\left(g\right)\)
\(\Rightarrow m_{ddNaCl}=\frac{5,85.100}{10}=58,5\left(g\right)\)
m\(_{NaCl}=0,1.58,5=5,85\left(g\right)\)
mdd=\(\frac{5,85.100}{10}=58,5\left(g\right)\)
Chúc bạn học tốt
mNaCl= 0,1. 58,5= 5,85
=>mdd= 58,5(g)