\(m_C=0.95\left(tấn\right)=950\left(kg\right)\)
\(n_C=\dfrac{950}{12}=\dfrac{475}{6}\left(kmol\right)\)
\(C+O_2\underrightarrow{t^0}CO_2\)
\(\dfrac{475}{6}.\dfrac{475}{6}\)
\(m_{O_2}=\dfrac{475}{6}\cdot32=2533.3\left(kg\right)=2.5333\left(tấn\right)\)