-x-3=-(x+3) ; -x+3=-(x-3) ; x2-9= (x+3)(x-3)
MTC: (x+3)(x-3)
\(\frac{2}{-x-3}+\frac{3}{-x+3}\)\(+\frac{x^2+11x+12}{x^2-9}\) =\(\frac{\left(-2x+6\right)+\left(-3x-9\right)+\left(x^2+11x+12\right)}{\left(x+3\right)\left(x-3\right)}\)=\(\frac{x^2+6x+9}{\left(x+3\right)\left(x-3\right)}\)=\(\frac{\left(x+3\right)^2}{\left(x+3\right)\left(x-3\right)}\)=\(\frac{x+3}{x-3}\)