Question

Tính đạo hàm của hàm số sau:

y=\(\dfrac{x^5}{5}+\sqrt{x}-\dfrac{1}{x}+\dfrac{1}{x^3}-2\)

Answer 1

\(y'=\dfrac{1}{5}\cdot5x^4+\dfrac{1}{2\sqrt{x}}+\dfrac{1}{x^2}+\dfrac{-\left(x^3\right)'}{x^6}\)

\(=x^4+\dfrac{1}{2\sqrt{x}}+\dfrac{1}{x^2}+\dfrac{-3x^2}{x^6}=x^4+\dfrac{1}{2\sqrt{x}}+\dfrac{1}{x^2}-\dfrac{3}{x^4}\)