Question

Tính bằng cách thuận tiện nhất: 

a,1\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) x 1\(\dfrac{1}{5}\) : 1\(\dfrac{1}{6}\) x 1\(\dfrac{1}{7}\) x1\(\dfrac{1}{8}\) =                            b, 1\(\dfrac{1}{3}\) : 1\(\dfrac{1}{4}\) : 1\(\dfrac{1}{5}\) : 1\(\dfrac{1}{6}\) : 1\(\dfrac{1}{7}\) :1\(\dfrac{1}{8}\) =    

Answer 1

a: \(=\dfrac{4}{3}\cdot\dfrac{5}{4}\cdot\dfrac{6}{5}\cdot\dfrac{7}{6}\cdot\dfrac{8}{7}\cdot\dfrac{9}{8}=\dfrac{9}{3}=3\)

b: \(=\dfrac{4}{3}:\dfrac{5}{4}:\dfrac{6}{5}:\dfrac{7}{6}:\dfrac{8}{7}:\dfrac{9}{8}\)

\(=\dfrac{16}{27}\)