Question

Tính:

a) \(\frac{x^3}{2y\left(x-2y\right)}\): \(\frac{x^2}{2x^2y-8y^3}\)

Answer 1

a)\(\frac{x^3}{2y\left(x-2y\right)}\):\(\frac{x^2}{2x^2y-8y^3}\)

=\(\frac{x^3}{2y\left(x-2y\right)}:\frac{x^2}{2y\left(x^2-4y^2\right)}\)

=\(\frac{x^3}{2y\left(x-2y\right)}:\frac{x^2}{2y\left(x-2y\right)\left(x+2y\right)}\)

=\(\frac{x^3}{2y\left(x-2y\right)}.\frac{2y\left(x-2y\right)\left(x+2y\right)}{x^2}\)

=x.(x+2y)

=x²+2xy