Lơ giải:
$\frac{1+5y}{5x}=\frac{1+7y}{4x}$
$\Rightarrow \frac{1+5y}{5}=\frac{1+7y}{4}$
$\Rightarrow 4(1+5y)=5(1+7y)$
$\Rightarrow 4+20y=5+35y$
$\Rightarrow 1=-15y\Rightarrow y=\frac{-1}{15}$
Có:
$\frac{1+5y}{5x}=\frac{1+3y}{12}$
$5x=(1+5y): \frac{1+3y}{12}=\frac{12(1+5y)}{1+3y}=\frac{12(1+5.\frac{-1}{15})}{1+3.\frac{-1}{15}}=10$
$\Rightarrow x=2$