\(x-2xy+y-3=0\)
\(\Leftrightarrow2x-4xy+2y-6=0\)
\(\Leftrightarrow2x-4xy+2y-1-5=0\)
\(\Leftrightarrow2x\left(1-2y\right)+\left(2y-1\right)=5\)
\(\Leftrightarrow-2x\left(2y-1\right)+\left(2y-1\right)=5\)
\(\Leftrightarrow\left(-2x+1\right)\left(2y-1\right)=5\)
\(\Leftrightarrow\left\{{}\begin{matrix}-2x+1=5\\2y-1=1\end{matrix}\right.\)hoặc \(\left\{{}\begin{matrix}-2x+1=1\\2y-1=5\end{matrix}\right.\)
hoặc \(\left\{{}\begin{matrix}-2x+1=-5\\2y-1=-1\end{matrix}\right.\) hoặc\(\left\{{}\begin{matrix}-2x+1=-1\\2y-1=-5\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=1\end{matrix}\right.\)hoặc \(\left\{{}\begin{matrix}x=0\\y=3\end{matrix}\right.\)
hoặc \(\left\{{}\begin{matrix}x=3\\y=0\end{matrix}\right.\) hoặc \(\left\{{}\begin{matrix}x=1\\y=-2\end{matrix}\right.\)
Vậy có 4 cặp x,y thỏa mãn là....