\(x^3+6x^2+12x+8=0\)
\(< =>\left(x+2\right)^3=0\)
x+2=0 suy ra x = -2
\(x^3+6x^2+12x+8=0\)
\(< =>\left(x+2\right)^3=0\)
x+2=0 suy ra x = -2
Tìm x biết:
\(a)x^3-6x^2+12x-8=0\\ b)8x^3-12x^2+6x-1=0\\ c)x^3+9x^2+27x+27=0\)
TÌm x
a) x^2 - 12x +11 = 0
b) 4x^2 - 4x - 3 = 0
c) 4x^2 - 12x - 7 = 0
d) x^3 - 6x^2 = 8 - 12x
Giúp mình với nhanh nhanh nhé, cảm ơn a) ( x^2 + x )^2 + 2( x^2 + x ) - 8 = 0 b) ( x^2 - 4x +3 ) ( x^2 +6x + 8 ) + 24 = 0 c) 6x^4 + 25x^3 + 12x^2 - 25x + 6 = 0 d) ( x - 2 )^4 + ( x- 3 )^4 = 0
BÀi 5
a) x^2 - 12 x + 11 = 0
b) 4x^2 - 4x - 3 = 0
c) 4x^2 - 12x - 7 = 0
d) x^3 - 6x^2 = 8 - 12x
1. 6x(x - 10) - 2x+20=0 6. 3x2 - 6x+3=0
2. 3x2(x - 3) + 3(3 - x)=0 7. 4x2 - 10x+2=0
3. x2 - 8x+16=2(x -4) 8. x2 - 12x -18=0
4. x2 - 16 + 7x ( x+4)=0 9. 3x2 - 10x+3=0
5. x2 - 13x - 14=0 10. 5x2 - 10x+10=0
b)N=12x+34/x^2+2
b)A=6x+8/x^2+1
c)B=6x+11/x^2-2x+3
d)N=6x+17/x^2+2
Giải pt: \(8\left(x-3\right)^3+x^3=6x^2-12x+8\)
Tim GTNN va GTLN :
b)N=12x+34/x^2+2
b)A=6x+8/x^2+1
c)B=6x+11/x^2-2x+3
d)N=6x+17/x^2+2
Tim GTNN va GTLN :
b)N=12x+34/x^2+2
b)A=6x+8/x^2+1
c)B=6x+11/x^2-2x+3
d)N=6x+17/x^2+2