\(x-2\sqrt{x}=0\)
<=> x2 = \(\left(2\sqrt{x}\right)^2\)
<=> x2 = 4x
<=> x2 - 4x = 0
<=> x(x-4) = 0
<=> \(\left[\begin{array}{nghiempt}x=0\\x=4\end{array}\right.\)
\(x-2\sqrt{x}=0\)
\(\Rightarrow x=2\sqrt{x}\)
\(\Rightarrow x^2=4x\)
\(\Rightarrow x=4\)
Vậy x = 4