Question

Tìm x trong các tỉ lệ thức sau

a) $\frac{x}{27}=\frac{-2}{3,6}$

b) -0,52 : x = -9,36: 16,38

c) $\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}$$=>3,6x=-2.27=>3,6x=-54=>x=-54:3,6=>x=-15$

$\mathrm{GIẢI\; CHI\; TIẾT\; CHO\; MÌNH\; NHA\; !}$

Answer 1

a) x/27=-2/3.6

Ta có: x.3,6=27.(-2)

<=>x.3,6=-54

<=>x=-54/3,6

<=>x=-15

Vậy x =-15

b) -0,52 : x = -9,36: 16,38

Ta có: -0,52/x=-4/7

<=>x=0.91

Vậy x=0.91

Answer 2

a) \(\dfrac{x}{27}=\dfrac{-2}{3,6}\) <=> \(x=\dfrac{27.\left(-2\right)}{3,6}\) <=> \(x=-15\) Vậy \(x=-15\) b) \(-0,52:x=-9,36:16,38\) \(-0,52:x=\dfrac{-4}{7}\) \(x=\dfrac{91}{100}\) Vậy \(x=\dfrac{91}{100}=0,91\)

Answer 3

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