Question

Tìm x, biết:

x+15%x=[(1,09-0,29).\(1\frac{1}{4}\)]:[(18,9-\(16\frac{13}{20}\)).\(\frac{8}{9}\)]

Answer 1

\(x+15\%x=\left[\left(1,09-0,29\right).1\frac{1}{4}\right]:\left[\left(18,9-16\frac{13}{20}\right).\frac{8}{9}\right]\)

\(x+15\%x=\left[0,8.1\frac{1}{4}\right]:\left[2,25.\frac{8}{9}\right]\)

\(x+15\%x=1:2\)

\(x+15\%x=\frac{1}{2}\)

\(x+15x=\frac{1}{2}\)

\(16x=\frac{1}{2}\)

\(x=\frac{1}{2}:16=\frac{1}{32}\)

Vậy x=1/32