Có: (x+5)+(x+10)+(x+15)+.....+(x+60)=450
x+5+x+10+x+15+...+x+60=450
12.x + (5+10+15+...+60)=450
12.x + 390 = 450
\(\Rightarrow12.x=60\Rightarrow x=5\).
Vậy x = 5.
\(\left(x+5\right)+\left(x+10\right)+..+\left(x+60\right)=450\)
\(\Leftrightarrow\left(x+x+...+x\right)+\left(5+10+...+60\right)=450\)
\(\Leftrightarrow12x+\dfrac{\left(5+60\right).12}{2}=450\)
\(\Leftrightarrow12x+390=450\)
\(\Leftrightarrow x=5\)