Ta có :
\(64^2=\left(4^3\right)^2=4^{3.2}=4^6\)
\(\Rightarrow\left(2x-1\right)^6=64^2\)
\(\Rightarrow\left(2x-1\right)^6=4^6\)
\(\Rightarrow2x-1=4\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=2,5\)
(2x - 1)^6 = 64^2
(2x - 1)^6 = (4^3)^2
(2x - 1)^6 = 4^6
=> 2x - 1 = 4
2x = 4 + 1
2x = 5
x = 5 : 2
x = 2,5
Vậy x = 2,5
\(\left(2x-1\right)^6=64^2\)
\(\Rightarrow\left(2x-1\right)^6=\left(4^3\right)^2=4^6\)
\(\Rightarrow\left(2x-1\right)=\left(\pm4\right)\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x-1=4\\2x-1=-4\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x=4+1=5\\2x=-4+1=-3\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=5:2=2,5\\x=-3:2=-1,5\end{array}\right.\)
Vậy : \(\left[\begin{array}{nghiempt}x=2,5\\x=-1,5\end{array}\right.\)