Question

Tìm \(x:\)

\(3x+3x+1+3x+2=117\)

Answer 1

\(3x+3x+1+3x+2=117\)

\(\Rightarrow3x+3x+3x=117-1-2\)

\(\Rightarrow3x+3x+3x=114\)

\(\Rightarrow x.\left(3+3+3\right)=114\)

\(\Rightarrow x.9=114\)

\(\Rightarrow x=\dfrac{38}{3}\)

Vậy \(x=\dfrac{38}{3}\)

Answer 2

=> 3x+3x+3x+1+2=117

=>9x+3=117

=>9x=117-3=114

=> x=\(\dfrac{114}{9}\)

Answer 3

\(3x+3x+1+3x+2=117\)

\(\Leftrightarrow9x=114\)

\(\Leftrightarrow x=\dfrac{38}{3}\)

Answer 4

3x+3x+1+3x+2=117

=> 3x+3x+3x+1+2=117

=> 9x+3=117

=> 9x= 114

=> x= 114/9

=> x = 8/3

Answer 5

3x+3x+1+3x+2 =117

3x.(1+2)=117

3x.3=117

3x=117:3

3x=39

x=39:3

x=13

Answer 6

\(3x+3x+1+3x+2=117\)

\(9x+3=117\)

\(9x=114\)

\(x=\dfrac{114}{9}=\dfrac{38}{3}\)

Answer 7

\(3x+3x+1+3x+2=117\)

\(9x+3=117\)

\(9x=114\)

\(x=\dfrac{114}{9}=\dfrac{38}{3}\)