Question

\(3x+3x+1+3x+2=117\)

tìm x

Answer 1

3x+3x+1+3x+2=177

9x+3=117

9x=117-3

9x=114

x=114/9

Answer 2

\(3x+3x+1+3x+2=117\)

\(\Leftrightarrow\left(3x+3x+3x\right)+\left(1+2\right)=117\)

\(\Leftrightarrow9x+3=117\)\(\Rightarrow9x=114\Rightarrow x=\frac{114}{9}\)

\(\text{Vậy x=}\frac{114}{9}\)

Answer 3

3x+3x+1+3x+2=117

=>3x.3 +(1+2) = 117

=>9x +3 = 117

=> 9x = 114

=> x = \(\frac{38}{3}\)

Answer 4

\(3^x\)+ 3 · \(3^x\)+ 3² · \(3^x\) = 117
ký hiệu là \(3^x\)= t
t + 3t + 9t = 117
13T = 117
t = 117/13
t = 9
\(3^x\) = 9
\(3^x\) = 3²
x = 2