Question

Tìm tập xác định của hàm ssos sau

1 , \(y=\frac{\sqrt{x}}{\left(x-1\right)\left(x-2\right)}\)

2 , \(y=\sqrt{2x^2-3x+1}+\sqrt{x-1}\)

Answer 1

1,ĐK:\(\left\{{}\begin{matrix}x\ge0\\x\ne1\\x\ne2\end{matrix}\right.\) \(\Rightarrow\) D = [0;1)\(\cup\)(1;2)\(\cup\)(2;\(+\infty\))

2,ĐK: \(\left\{{}\begin{matrix}2x^2-3x+1\ge0\\x-1\ge0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}x\le\frac{1}{2}\\x\ge1\end{matrix}\right.\\x\ge1\end{matrix}\right.\) \(\Rightarrow x\ge1\)

D = [1;\(+\infty\))