\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=720:20\)
\(41-\left(2x-5\right)=18\)
\(2x-5=41-18\)
\(2x=23+5\)
\(x=28:2=14\)
Chứng minh rằng :
a)\(\dfrac{1}{x}\)-\(\dfrac{1}{x+a}=\dfrac{a}{x\left(x+a\right)}\)
b)\(\dfrac{1}{x\left(x+1\right)}-\dfrac{1}{\left(x+1\right)\left(x+2\right)}=\dfrac{2}{x\left(x+1\right)\left(x+2\right)}\)
c)\(\dfrac{1}{x\left(x+1\right)\left(x+2\right)}-\dfrac{1}{\left(x+1\right)\left(x+2\right)\left(x+3\right)}=\dfrac{3}{x\left(x+1\right)\left(x+2\right)\left(x+3\right)}\)
Tìm x
a, \(311-x+82=46+\left(x-21\right)\)
b,\(-\left(x-3+85\right)=\left(x+70-71\right)-5\)
c,\(-2\left(x+6\right)+6\left(x-10\right)=8\)
d,\(\left|x\right|=41\)
e, \(\left|-8\right|.\left|x\right|=\left|-56\right|\)
f,\(3.\left|x-2\right|+2x=19\) với \(x\) \(\ge\) 2
Giúp hộ đi ạ, cảm ơn.
1: rút gọn rồi tính
\(\left(-\dfrac{72}{40}-\dfrac{144}{60}-2\dfrac{1}{3}\right)\) : \(\left(\dfrac{45}{100}-\dfrac{25}{60}+-\dfrac{75}{25}\right)\)
2: tìm x: \(3\cdot\left(4-x\right)+\left(x+2\right)\cdot\left(1+2x\right)=7\cdot\left(1+x\right)-2x\cdot\left(2-x\right)\)
3: tìm x: \(\dfrac{2\cdot\left(1+x\right)}{3}-\dfrac{5\cdot\left(2-x\right)}{6}=1\dfrac{1}{3}-\dfrac{3\cdot\left(2x+3\right)}{4}-1\dfrac{1}{2}\cdot\left(x+1\right)\)
4: cho a= \(3+3^{2^3}+3^3+3^4+...+3^{360}\)
Tìm x:
a,\(x^2\) - 9 = 0
b,\(\left(x-3\right)^2-25=0\)
c,\(\left(x-3\right)\left(2x-5\right)=0\)
d,\(\left(x-3\right)\cdot x-2\left(x-3\right)=0\)
e,\(3x\left(x-1\right)-5\left(1-x\right)=0\)
g,\(x^2+6x-7=0\)
h,\(2x^2+5x-7=0\)
Tìm x, biết:
\(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-1}{4}\)
Tìm số nguyên x biết :\(\left(x+1\right)\left(x+2\right)\left(x+3\right)...\left(x+100\right)\)
1.Tìm x,y
a)\(\left|x\right|\)=2017
b)\(\left|x\right|\)=\(\left|2017\right|\)
c)\(\left|x\right|\)+\(\left|y\right|\)=0
d)\(\left|x+5\right|\)+\(\left|y-3\right|\)=0
f)\(\left|x+2\right|\)=\(-5\)
Bài 1: Phá dấu ngoặc rồi tính:
a)\(\left(a+b+c\right)-\left(a-b+c\right)\)
b)\(\left(4.x+5.y\right)-\left(5.x-4.y-1\right)\)
Bài 2: Chứng minh bất đẳng thức:
a)\(\left(a+b+c+d\right)-\left(a-b-c+d\right)+1=a-\left(a-2b-2c-d\right)+\left(d+1\right)\)
b)\(\left(4x-3y+2\right)-\left(3x-4y+2\right)=\left(2x+2y\right)-\left(x+y\right)\)