2n+2n+1=24
=>2n(1+21)=24
=>2n=24:(1+2)
=>2n=8
=>2n=23
=>n=3
Vậy n=3
\(2^n+2^{n-1}=24\)
\(2^n\left(1+2\right)=24\)
\(2^n.3\)=24
\(2^n=24:3\)
\(2^n=8\)
\(2^n=2^3\)
n=3
vay n=3
\(2^n+2^{n+1}=24\)
\(\Rightarrow2^n\left(2+1\right)=24\)
\(\Rightarrow2^n.3=24\)
\(\Rightarrow2^n=24:3=8\)
\(\Rightarrow2^n=2^3\)
\(\Rightarrow n=3\)
Vậy..................