\(\frac{x+2}{\sqrt{x}}=\frac{x}{\sqrt{x}}+\frac{2}{\sqrt{x}}=\sqrt{x}+\frac{2}{\sqrt{x}}\)
AD co-si cho 2 số dương
\(\sqrt{x}+\frac{2}{\sqrt{x}}\ge2\sqrt{\sqrt{x}\frac{2}{\sqrt{x}}}=2\sqrt{2}\)
Dấu bằng xảy ra
\(\sqrt{x}=\frac{2}{\sqrt{x}}\Rightarrow x=2\)