Question

Tìm giới hạn sau: \(\lim\limits_{x\rightarrow+\infty}\dfrac{x^2-x}{x}\)

Answer 1

\(\lim\limits_{x\rightarrow+\infty}\dfrac{x^2-x}{x}=\lim\limits_{x\rightarrow+\infty}\dfrac{x\left(x-1\right)}{x}=\lim\limits_{x\rightarrow+\infty}x-1=+\infty\)