\(\dfrac{40^{30}.3^{43}}{2^{57}.27^{15}}=\dfrac{\left(2^3.5\right)^{30}.3^{43}}{2^{57}.\left(3^3\right)^{15}}=\dfrac{2^{90}.5^{30}.3^{43}}{2^{57}.3^{45}}\)
\(=\dfrac{2^{33}.2^{57}.5^{30}.3^{43}}{2^{57}.3^{43}.3^2}=\dfrac{2^{33}.5^{30}}{3^2}=\dfrac{2^{33}.5^{30}}{9}\)
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