Lời giải:
Áp dụng công thức: \(a^3-b^3=(a-b)^3+3ab(a-b)\) ta có:
\((\sqrt[3]{4}+1)^3-(\sqrt[3]{4}-1)^3=[(\sqrt[3]{4}+1)-(\sqrt[3]{4}-1)]^3+3(\sqrt[3]{4}+1)(\sqrt[3]{4}-1)[(\sqrt[3]{4}+1)-(\sqrt[3]{4}-1)]\)
\(=2^3+3(\sqrt[3]{4^2}-1).2\)
\(=8+6(\sqrt[3]{16}-1)=2+6\sqrt[3]{16}\)