tóm tắt: mcu =600g=0,6kg, mh2o=0,4l=0,4kg
t1= \(95^o\)c, t2=\(28^oc\)
ccu=380J/kg.k, ch2o=4200J/kg.k
a, tính Qcu
b, th2o
bài làm
a,Qcu=mcu.ccu.(t1-t2)
=0,6.380.(95-28)
=15276J
b, th2o=\(\frac{Q^{_{H20}}}{m_{h2o}.c_{h2o}}\)
= \(\frac{m_{h20}.c_{h20}\left(t_1-t_2\right)}{c_{h2o}.m_{h2o}}\)
=t1-t2
=95-28=67