Question

\(\sqrt{2+\sqrt{2}}+\frac{1}{\sqrt{18}}-\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{24}}\)

Answer 1

Bạn không nêu rõ yêu cầu đề bài.

Nếu là rút gọn thì:

\(\sqrt{2+\sqrt{2}}+\frac{1}{\sqrt{18}}-\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{24}}=\sqrt{2+\sqrt{2}}+\frac{\sqrt{2}}{\sqrt{36}}-\frac{\sqrt{6}(\sqrt{2}-1)}{\sqrt{6}.\sqrt{4}}\)

\(=\sqrt{2+\sqrt{2}}+\frac{\sqrt{2}}{6}-\frac{\sqrt{2}-1}{2}=\sqrt{2+\sqrt{2}}+\frac{\sqrt{2}}{6}-\frac{3\sqrt{2}-3}{6}\)

\(=\sqrt{2+\sqrt{2}}+\frac{3-2\sqrt{2}}{6}\)