ta có: \(\dfrac{1}{M}=\dfrac{101^{103}+1}{101^{102}+1}=\dfrac{101^{103}+101-100}{101^{102}+1}=1-\dfrac{100}{101^{102}+1}\)
\(\dfrac{1}{N}=\dfrac{101^{104}+1}{101^{103}+1}=\dfrac{101^{104}+101-100}{101^{103}+1}=1-\dfrac{100}{101^{103}+1}\)
vì \(\dfrac{100}{101^{102}+1}>\dfrac{100}{101^{103}+1}\Rightarrow1-\dfrac{100}{101^{102}+1}< 1-\dfrac{100}{101^{103}+1}\Rightarrow\dfrac{1}{M}< \dfrac{1}{N}\Rightarrow M>N\)